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AMC 10 and AIME problem archive

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Problems

Official solutions

  • AMC 10A 2014 · #1850

    What is 10(12+15+110)110\cdot\left(\tfrac{1}{2}+\tfrac{1}{5}+\tfrac{1}{10}\right)^{-1}?

  • AMC 10A 2024 · #1850

    What is the value of 9,9011019910,1019,901\cdot101-99\cdot10,101?

  • AMC 10 2000 · #201515

    Let AA, MM, and CC be nonnegative integers such that A+M+C=10A+M+C=10. What is the maximum value of AMC+AM+MC+CAA\cdot M\cdot C+A\cdot M+M\cdot C+C\cdot A?

Open event · try it nowrated 1150

At a party, each of the 88 guests shakes hands exactly once with every other guest. How many handshakes occur?

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03

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AMC 10

2000 – 2025

1,021

AIME

1983 – 2025

929

ProblemLab originals

with full solutions

27

Topics from linear equations to modular arithmetic, tagged on 24 skills

After a miss · AMC 10A 2019 #17

Case 1: the red cube is excluded. Arranging one red, three blue, and four green cubes gives 8!4!3!=280\frac{8!}{4!\cdot 3!}=280 arrangements…

Solution 1Solution 2 Casework video

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